8x^2-15+14x=0

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Solution for 8x^2-15+14x=0 equation:



8x^2-15+14x=0
a = 8; b = 14; c = -15;
Δ = b2-4ac
Δ = 142-4·8·(-15)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-26}{2*8}=\frac{-40}{16} =-2+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+26}{2*8}=\frac{12}{16} =3/4 $

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